// Copyright (C) 2010-2019 Free Software Foundation, Inc. // // This file is part of the GNU ISO C++ Library. This library is free // software; you can redistribute it and/or modify it under the // terms of the GNU General Public License as published by the // Free Software Foundation; either version 3, or (at your option) // any later version. // // This library is distributed in the hope that it will be useful, // but WITHOUT ANY WARRANTY; without even the implied warranty of // MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the // GNU General Public License for more details. // // You should have received a copy of the GNU General Public License // along with this library; see the file COPYING3. If not see // . // This file uses the chi^2 test to measure the quality of a hash // function, by computing the uniformity with which it distributes a set // of N strings into k buckets (where k is significantly greater than N). // // Each bucket has B[i] strings in it. The expected value of each bucket // for a uniform distribution is z = N/k, so // chi^2 = Sum_i (B[i] - z)^2 / z. // // We check whether chi^2 is small enough to be consistent with the // hypothesis of a uniform distribution. If F(chi^2, k-1) is close to // 0 (where F is the cumulative probability distribution), we can // reject that hypothesis. So we don't want F to be too small, which // for large k, means we want chi^2 to be not too much larger than k. // // We use the chi^2 test for several sets of strings. Any non-horrible // hash function should do well with purely random strings. A really // good hash function will also do well with more structured sets, // including ones where the strings differ by only a few bits. #include #include #include #include #include #include #include #include #include #include #include #ifndef SAMPLES #define SAMPLES 300000 #endif template double chi2_hash(const Container& c, long buckets) { std::vector counts(buckets); std::hash hasher; double elements = 0; for (auto i = c.begin(); i != c.end(); ++i) { ++counts[hasher(*i) % buckets]; ++elements; } const double z = elements / buckets; double sum = 0; for (long i = 0; i < buckets; ++i) { double delta = counts[i] - z; sum += delta*delta; } return sum/z; }